Math, asked by tristinapegu44, 2 months ago

1+tan^2/1+cot^2=tan^2 plz send me the correct answer it's really urgent​

Answers

Answered by vipinkumar212003
1

Answer:

 \frac{1 +  { \tan }^{2}x }{1 +   { \cot }^{2} x}  =  { \tan }^{2} x \\ \color{blue}{ \underline{Take \: L.H.S}:}  \\ \frac{1 +  { \tan }^{2}x }{1 +   { \cot }^{2} x}  =  \frac{ { \sec }^{2}x }{ { \cosec}^{2}x }   =  \frac{ \frac{1}{ { \cos}^{2}x } }{ \frac{1}{ { \sin}^{2} x} }  \\   =  \frac{ { \sin}^{2}x }{ { \cos}^{2}x }  \\ \\   =  { \tan}^{2} x = R.H.S \\  \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}

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