explain how root 6 is an irrational number
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NOTE: $\sqrt 6 = \dfrac{a}{b}$ , this representation is in lowest terms and hence, a and b have no common factors.So it is an irrational number.
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When we calculate the value of √6, we get √6 = 2.449489742783178... It is a decimal number that does not terminate and terms are not repeating themselves after the decimal point. Thus, the value obtained for the root of 6 satisfies the condition of being a non-terminating and non-repeating decimal number that keeps extending further after the decimal point which makes √6 an irrational number.
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