Question

1+tan^2 A = ? please tell me the answer guys ​

Answer 1

Step-by-step explanation:

sec²A-tan²A=1

sec²A= 1+tan²A

Answer 2

$\sf\red{\underline{\underline{Answer:}}}$

$\sf{1+tan^{2}A=sec^{2}A}$

$\sf\green{\underline{\underline{Solution:}}}$

$\sf{According \ to \ identity}$

$\sf{sec^{2}\theta-tan^{2}\theta=1}$

$\sf{\therefore{sec^{2}\theta=1+tan^{2}\theta}}$

$\sf{i.e. \ 1+tan^{2}\theta=sec^{2}\theta}$

$\sf{\therefore{1+tan^{2}A=sec^{2}A}}$

$\sf\blue{\underline{\underline{Extra \ information:}}}$

$\sf{Identities:-}$

$\sf{1) \ sin^{2}\theta+cos^{2}\theta=1}$

$\sf{2) \ sec^{2}\theta-tan^{2}\theta=1}$

$\sf{3) \ cosec^{2}\theta-cot^{2}\theta=1}$

$\sf{Ratios:}$

$\sf{1) \ cosec\theta=\frac{1}{sin\theta}}$

$\sf{2) \ sec\theta=\frac{1}{cos\theta}}$

$\sf{3) \ tan\theta=\frac{sin\theta}{cos\theta}}$

$\sf{4) \ cot\theta=\frac{1}{tan\theta}}$

$\sf{5) \ tan\theta=\frac{sec\theta}{cosec\theta}}$

$\sf{6) \ cot\theta=\frac{cosec\theta}{sec\theta}}$