Question

1 + tan ^2 A = sec ^2 A​

Answer 1

Answer:

So what we have to do?

Yes it is correct

Answer 2

Here ,

□ formulas....

● tan A = sin A / cos A

● sec A = 1 / cos A

● sin^2A + cos^2A = 1

now ,

LHS

$= 1 + {tan}^{2} A \: \\ \\ = 1 + \frac{ {sin}^{2} A}{ {cos}^{2} A} \\ \\ take \: lcm \\ \\ = \frac{ {cos}^{2} A + {sin}^{2} A}{ {cos}^{2} A} \\ \\ = \frac{1}{ {cos}^{2} A} \\ \\ = {sec}^{2} A \:$

= RHS

Hope it helps.....

□ follow me...

● keep smiling &

always shining.............:-)