1-tan^2α/tan^2α-1 =tan^2α
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Answer:
FIRST OF ALL THE QUESTION WAS NOT 1-TAN^2ALPHA/TAN^2ALPHA-1=TAN^2ALPHA. IT WAS[ 1-TAN ALPHA/1-COT ALPHA]^2=TAN^2ALPHA.
SO, [1-TAN ALPHA/1-1/COT ALPHA]^2
=[1-TANA/TAN A-1*TAN A]^2
{-[-1+TAN A]/TAN A-1*TAN A}
=[-TAN A]^2
=TAN^2 A
Step-by-step explanation:
boo9o:
thanks
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