Math, asked by boo9o, 1 year ago

1-tan^2α/tan^2α-1 =tan^2α​

Answers

Answered by satakshisinha321
1

Answer:

FIRST OF ALL THE QUESTION WAS NOT 1-TAN^2ALPHA/TAN^2ALPHA-1=TAN^2ALPHA. IT WAS[ 1-TAN ALPHA/1-COT ALPHA]^2=TAN^2ALPHA.

SO, [1-TAN ALPHA/1-1/COT ALPHA]^2

=[1-TANA/TAN A-1*TAN A]^2

{-[-1+TAN A]/TAN A-1*TAN A}

=[-TAN A]^2

=TAN^2 A

Step-by-step explanation:


boo9o: thanks
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