1-tan^2 theta/1+tan^2 theta=1/2 find theta
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(1-tan²@)/(1+tan²@) = 1/2,
2-2tan²@ = 1+tan²@,
then
2-1=tan²@+2tan²@,
1=3tan²@,
hence
tan²@=1/3,
tan@=1/√3,
tan@=tan30°,
therefore
@=30°
2-2tan²@ = 1+tan²@,
then
2-1=tan²@+2tan²@,
1=3tan²@,
hence
tan²@=1/3,
tan@=1/√3,
tan@=tan30°,
therefore
@=30°
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