Math, asked by dk03852, 1 month ago

1-tan ²45/
1+ tan^2 45​

Answers

Answered by kamalhajare543
56

Answer:

Answer:

 \sf \: Value \: of \: \frac{1-tan^{2}45}{1+tan^{2}45}=0

Step-by-step explanation:

 \begin{gathered} \sf \: Value \: of \: \frac{1-tan^{2}45}{1+tan^{2}45}\\ \\  \sf= \pink{\frac{1-1}{1+1}}\end{gathered}

\* We know that

\begin{gathered}= \tan45° =  \: \frac{0}{2}=0\end{gathered}

Therefore,.

 \red{  \sf\: Value \: of \bold{ \frac{1-tan^{2}45}{1+tan^{2}45}=0}}

Hence This is Answer

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