(1+tan^2A)(1+cot^2A)=1/sin^2A-sin^4
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Answer:
Step-by-step explanation:
The answer won't be equal to RHSit will be equal if the question is:
(1 + 1/tan²A)(1 + 1/cot²A) = 1/(sin²A - sin^4.A),
LHS,
= (1 + 1/tan²A)(1 + 1/cot²A),
= ((tan²A+1)/tan²A)((cot²A+1)/cot²A),
= (sec²A/tan²A)(csc²A/cot²A),
= (sec²A.csc²A)/(tan²A.cot²A),
= sec²A.csc²A,
= 1/(sin²A.cos²A),
= (1/sin²A)(1/cos²A),
= (1/sin²A)(1/(1-sin²A)),
= 1/(sin²A - sin^4.A),
= RHS.
Hope it helps.
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