1-tan^2a=2tana/1-tan^2a
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It may be like this,
tan (2A) = 2tanA/(1-tan²A)
We know that,

Now ,
LHS = tan(2A)
=tan(A+A)
=
=
= $RHS$
••••
tan (2A) = 2tanA/(1-tan²A)
We know that,
Now ,
LHS = tan(2A)
=tan(A+A)
=
=
= $RHS$
••••
Soumok:
osm
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