(1+tan^2theta) cot theta\cosec^2 theta= tan theta
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The answer is given in the attachment.
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Step-by-step explanation:
Let theta =A
( 1- tan^2A)/(cof^2A-1)= tan^2A
L.H.S.
=(1-tan^2A)/(cot^2A-1)
=(1-tan^2A)/( 1/tan^2A. - 1)
=(1-tan^2A)/{(1-tan^2A)/tan^2A}
=(1-tan^2A)×tan^2A/(1-tan^2A)
= tan^2A. Proved.
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