1 = tan" (3x-2
1-3X²
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Solution:
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Step-by-step explanation:
y=tan−1(1−3x23x−x3)
Put x=tanθ
⇒y=tan−1(1−3tan2θ3tanθ−tan3θ)
=tan−1tan(3θ)=3θ=3tan−1x
∴dxdy=1+x23
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