1-tan^4x/1-tan^2x = 2-sec^x
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1-tan^4(x)/sec^2(x)=1-tan^2(x) , you need to use the difference of two squares method.
Working with the left side of the equation:
1-tan4(x) = ( 1- tan2(x)) (1 + tan2(x)) then you have ( 1- tan2(x)) (1 + tan2(x)) / sec2(x)
but sec2(x) = ( 1 + tan2(x)) ( Trigonometric identities )
Then the expression becomes ( 1- tan2(x)) (sec2(x)) / sec2(x) , and sec2(x) cancels out from both
the numerator and the denominator and you are left with ( 1- tan2(x)) , which is what you have on the right side of the equation.
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