1 tan 50° + sec 50

cot 40+cosec 40°
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Answer:
Value of \frac{(tan50+sec50)}{(cot40+cosec40)}+cos40\times cosec50 < /p > < p > =2
(cot40+cosec40)
(tan50+sec50)
+cos40×cosec50</p><p>=2
Step-by-step explanation:
Given
\frac{(tan50+sec50)}{(cot40+cosec40)}+cos40\times cosec50
(cot40+cosec40)
(tan50+sec50)
+cos40×cosec50
=\frac{tan(90-40)+sec(90-40)}{(cot40+cosec40)}+cos40\times cosec(90-40)
(cot40+cosec40)
tan(90−40)+sec(90−40)
+cos40×cosec(90−40)
= \frac{(cot40+cosec40)}{(cot40+cosec40)}+cos40\times sec40
(cot40+cosec40)
(cot40+cosec40)
+cos40×sec40
=1+cos40 \times \frac{1}{cos40}1+cos40×
cos40
1
= 1+11+1
=22
Therefore,
Value of \frac{(tan50+sec50)}{(cot40+cosec40)}+cos40\times cosec50=2
(cot40+cosec40)
(tan50+sec50)
+cos40×cosec50=2
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