Math, asked by prashantdhuaml27, 11 months ago

[1-tan(90°–θ) + sec(90°–θ)]/[tan(90°–θ) + sec(90°–θ)+1]=?

Answers

Answered by hrushikollaji9948

0

Step-by-step explanation:

this problems shows that sec (90-0) ×sectheta=RHS

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