(1+tan theta) (1+cot theta)=
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(1 + tan theta) (1 + cot theta)
For a easy-proceeding calculation, i am holding "THETAS" as "x" here.
So, (1 + tan x) (1 + cot x)
= 1 + cot x + tan x + tan x cot x
= 2 + tan x + cot x
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