Question

1/(tan theta + cot theta)

Answer 1

Answer:

Step-by-step explanation:

1/(tan theta + cot theta)

tan theta+cot theta:

sin theta/cos theta + cos theta/sin theta

sin^2 theta + cos^2 theta/sin theta*cos theta (LCM)

1/sin theta*cos theta (sin^2 theta + cos^2 theta=1)

By substituting this value,we get:

1/1/sin theta*cos theta

sin theta*cos theta

Answer 2

Answer:

1/sinθcosθ

Step-by-step explanation:

1/tanθ + 1/cotθ

cosθ/sinθ + sinθ/cosθ

taking LCM sinθcosθ,

cosθ × cosθ/sinθcosθ   +   sinθ × sinθ/cosθsinθ

cos²θ + sin²θ/sinθcosθ

1/sinθcosθ …..[∵sin²θ+cos²θ=1]