(1+TAN Theta)whole square +(1-Tan theta)whole square
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Answer:
2sec²θ
Step-by-step explanation:
( 1 + tan θ)²+ ( 1- tanθ)² = 1 + tan²θ + 2 tanθ + 1 + tan²θ - 2 tanθ
= 2+ 2 tan²θ =2(1+ tan²θ) = 2sec²θ
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