Question

1 + tan² A/1 + Sec A = sec A​

Answer 1

Answer:

Given Equation is (1 + tan^2A/(1 + secA)).

We know that tan^2A + 1 = sec^2A.

tan^2A = sec^2A - 1.

1 + \frac{sec^2A - 1}{1 + secA}1+

1+secA

sec

2

A−1

1 + \frac{(secA + 1)(secA - 1)}{1 + secA}1+

1+secA

(secA+1)(secA−1)

1 + secA - 11+secA−1

secA.

LHS = RHS.

Hope this helps!