Question

1 + tan2(x) = sec2(x) ​

Answer 1

Answer:

$cos^2 x+sin^2 x=1$

Divide both sides by $cos^2 x$, we get:

$\sf \dfrac{cos^2 x}{cos^2 x}+\dfrac{sin^2 x}{cos^2 x}=\dfrac{1}{cos^2 x}$

$\sf 1+tan^2 x=sec^2 x$

Hope it helps