40 students received merit-certificates in Mathematics,25 in Physics and 20 in Chemistry. In all,60 students got certificates.The number of students meritorious in all the three subjects is 5. How many students were meritorious in exactly two subjects?
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1
Answer:
80
Step-by-step explanation:
40 - Math
25 - Physics
20 - Chemistry
60 - Total students
5 - meritorious
Let A be the set of students in chemistry class and B be the set of students in physics class. It is given that n(A)=40 and n(B)=60.
If two classes meet at different timings then there can be some student sitting in both the classes.
Therefore, n(A∩B)=20
n(A∪B)=n(A)+n(B)−n(A∩B)
=40+60−20=80.
Answered by
1
Answer:
Thus, Final answer is 80
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