Question

(1+tan2A )+ (1+ 1/tan2A ) = (1/ sin2A -sin4A)​

Answer 1

Use the double-angle formula for cos,

sec2A=11–2sin2A

Using the definition of tan,

sec2A=11–2tan2Acos2A

Using the definition of sec and pythagorean identities,

sec2A=11−2tan2Asec2A=11−2tan2A1+tan2A

Then multiply through 1+tan2A1+tan2A,

sec2A=1+tan2A1+tan2A−2tan2A=1+tan2A1−tan2A

Answer 2

Hope it helps you!!!!!!!!