Question

Pls answer to questions

Answer 1

hope it's absolutely right

Answer 2

1. PARALLEL

2.

$\cos( \alpha ) = \frac{12}{13}$



$\cos( \alpha ) = \frac{b}{h}$

MEAN ☞☞☞

B = 12

H=13

$\sec( \alpha ) = \frac{h}{b}$
$= > \sec( \alpha ) = \frac{13}{12}$




$\tan( \alpha ) = \frac{p}{b}$


$- 1 + \: { \sec( \alpha ) }^{2} = { \tan( \alpha ) }^{2}$

$= > { \tan( \alpha ) }^{2} = - 1 + {( \frac{13}{12} )}^{2}$

$= > { \tan( \alpha ) }^{2} = - 1 + \frac{169}{144}$


$= > \frac{25}{144}$


$\tan( \alpha ) = \frac{5}{12}$