Math, asked by robertbenjamin499, 15 hours ago

[1+tan2A/1+cot2A]=[1-tanA/1-cotA]
(1 +  \tan ^{2} a \div  1 +   \cot^{2} a) = (1 -  \tan \:  a \div 1 -   \cot \: a) ^{2}   =  \tan^{2} a

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Answered by MysticSohamS
0

Answer:

hey here is your answer in above pics

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