Question

1+ tan²a/1+sec a=sec a​

Answer 1

Step-by-step explanation:

1+

1+secA

tan

2

A

=1+

1+secA

(sec

2

A−1)

=1+

(1+secA)

(secA−1)(secA+1)

=1+secA−1

=secA

⇒1+

1+secA

tan

2

A

=secA.