Question

（1+tanA+secA）（1+cotA-cosecA）​

Answer 1

Answer :2

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(1+tan+sec)(1+cot-cosec)

(1+sin/cos+1/cos)(1+cos/sin-1/sin)

((cos+sin+1)/cos)((sin+cos-1)/sin)          

((cos+sin)^2-1^2)/sin*cos                 {(a+b)(a-b)=a^2-b^2}

(cos^2+sin^2+2sin*cos-1)/sin*cos   {(a+b)^2=a^2+b^2+2ab}

(1+2sin*cos-1)/sin*cos

2sin*cos/sin*cos

2

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Answer 2

Answer:

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