(1+TanA+SecA)(1+cotA-cosecA) = 2
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L:H:S:
(1+tanA+secA)(1+cotA-cosecA)
= (1+sinA/cosA+ 1/cosA)(1+cosA/sinA-1/sinA)
=(cosA+sinA+1/cosA)(sinA+cosA-1/sinA)
= (sinA+cos)²-1/sinAcosA
= (sin²A+cos²A)+2sinAcosA-1/sinAcosA
= 2sinAcosA+1-1/sinA cosA
= 2(R:H:S)
hope it helps ✨✨___!!
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