Math, asked by Waleya, 1 year ago

(1+tanA)/sinA+(1+cotA)/cosA=2(cosecA+secA)

Answers

Answered by sandy1816

3

Step-by-step explanation:

(1+tana)/sina + (1+cota)/cosa

=(cosa+sina)/sinacosa+(sina+cosa)/sinacosa

=2(cosa+sina)/sinacosa

=2(1/sina+1/cosa)

=2(seca+coseca)

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