Math, asked by dk9252655, 9 months ago

(1+tanø+sec) (1+cotø -cosecø)

Answers

Answered by dalbagsinghdalbagtha

4

Answer:

1-tan2ø/cot2ø-1

1-sin2ø/cos2ø/cos2ø/sin2ø-1 {TAKING tanø=sinø/cosø}

By taking LCM , we get

cos2ø-sin2ø/cos2ø/cos2ø-sin2ø/sin2ø

1/cos2ø/1/sin2ø {by cutting cos2ø-sin2ø}

Therefore , sin2ø/cos2ø=tan2ø

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