(1+tanø+sec) (1+cotø -cosecø)
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Answer:
1-tan2ø/cot2ø-1
1-sin2ø/cos2ø/cos2ø/sin2ø-1 {TAKING tanø=sinø/cosø}
By taking LCM , we get
cos2ø-sin2ø/cos2ø/cos2ø-sin2ø/sin2ø
1/cos2ø/1/sin2ø {by cutting cos2ø-sin2ø}
Therefore , sin2ø/cos2ø=tan2ø
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