Question

1+Tansq.A/1+cotsq.A=

Answer 1

HOLA

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$\frac{1 \: + \: tan {}^{2} }{1 \: + \: cot {}^{2} } = \: what \\ \\ \\ tan \: = \: \frac{sin}{cos} \: \: \: \: cot \: = \: \frac{cos}{sin} \\ \\ \\ \frac{1 \: + \: ( \frac{sin}{cos}) {}^{2} } {1 \: + \: ( \frac{cos}{sin}) {}^{2} } \: \: \: (cancelation) \: \\ \\ \\ \frac{1}{1} = \: 1$

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HOPE U UNDERSTAND ❤❤

Answer 2

Hello mate

1+tan^2A/ 1+cot^2 A

1+tan^2 A = sec^2 A

and, 1 +cot^2A = Cosec^2A

The answer is Sec^2A/cosec^2A

sec= 1/cos , cosec = 1/sin

1/cos^2 A/ 1/sin^2 A

Sin^2A/Cos^2A = Sin^2A/1-Sin^2A

cancel Sin^2A

therefore, 1/1 = 1