Math, asked by alamavish, 3 months ago

1+tanx/sinx + 1+cotx/cosx=2(secx + cosecx)

Answers

Answered by amanraj56

0

Step-by-step explanation:

(1+tanx)/sinx + (1+cotx)/cosx

1/sinx+tanx/sinx + 1/cosx+cotx/cosx

1/sinx+tanx•cosecx+ 1/cosx+ cotx•secx

1/sinx+sinx/cosx•cosecx + 1/cosx+cosx/sinx•secx

1/sinx+1/cosx +1/cosx +1/sinx

cosecx +secx +secx +cosecx

2cosecx + 2secx

2(cosecx+secx)

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