Question

1)${\sf{if \:x+{\frac{1}{x}}=-3}}$${\sf{ then \:value\: of \:x^8+3x^7+x^6+5}}$

2)${\sf{if \:(x-2✓3)\: is\: a \:factor \:of\: polynomial \:x^2-✓3x-a\: then\: the \:value\: of \: ✓(a-2)}}$

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Class 10

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Answer 1

Answer:

1) 5

2) Question 2 is incomplete

Step-by-step explanation:

Given that, x +1/x =  -3

∴ x² + 1 = -3x

⇒ x² + 3x +1 =0, here we can also deduce that x is non zero.

Substituting this into the given expraession:

$x^{8} + 3x^{7} + x^{6} +5\\= x^{6}(x^{2} + 3x^{1} + x^{0}) +5\\= x^{6}(x^{2} + 3x + 1) + 5\\= x^{6}(0) + 5\\= 5$

Answer 2

Ques 2-: ${\sf{if \:(x-2✓3)\: is\: a \:factor \:of\: polynomial }}$${\sf{\:x^2-✓3x-a\: then\: the \:value\: of \: ✓(a-2)}}$

post it again

for 2 dots