Question

any brainy CAn solve this problem?​

Answer 1

Answer:

this might help you..

Step-by-step explanation:

Answer 2

Answer:

let the incomes of A,B and C be 7x ,9x and 12x respectively.

let the expenditures of A,BandC be 8y,9y and 15y respectively.

Therefore,

Savings of A,B and C are (7x–8y),(9x–9y)and(12x–15y)respectively.

Given,

A saves 1/4th of his income.

Or, (7x–8y)=1/4×7x

Or, 7x–8y=7x/4

Or, (7x–7x/4) =8y

Or, 21x/4=8y Or, y=21x/32.

Saving of A,B and C are :–

7x/4 : {9x– (9×21x)/32} :{12x–(15×21x)/32}

I.e., 7x/4:(288–189)x/32:(382–315)x/32

≡ 56x/32 : 99x/32 : 69x/32

≡56:99:69.