Question

1
$\sqrt{1 + 25 \div 144} = 1 + x \div 12$

Answer 1

[tex] \sqrt{1+ \frac{25}{144}} = 1 + \frac{x}{12} \\ \\ 1 + \frac{5}{12} = 1 + \frac{x}{12} \\ \\ \frac{12 + 5}{12} = 1 + \frac{x}{12} \\ \frac{17}{12} - 1 = \frac{x}{12} \\ \\ \frac{5}{12} = \frac{x}{12} \\ \\ Therefore it is proved that x = 5[/tex]