Question

1. The ages of A and B are in the ratio 3:5. Four years later, the sum of their ages is 48. Find
their present ages​

Answer 1

Answer:

See the attachment that I have attach

Step-by-step explanation:

hope it helps uhh

Answer 2

Answer:

${\textsf{Presently, A is 15 years old and B is 25 years old.}}$

Step-by-step explanation:

$\textsf{Ratio of their present ages = 3 : 5}$

$\textsf{Sum of their ages after 4 years = 48}$

$\textsf{\underline{Let the present ages be:}}$

• $\textsf{A = 3y}$
• $\textsf{B = 5y}$

$\textsf{\underline{Ages after 4 years:}}$

• $\textsf{A = (3y +4)}$
• $\textsf{B = (5y + 4)}$

___________________

$\textsf{\underline{According to the Question,}}$

Four years later, the sum of their ages is 48.

$\sf{\longrightarrow} \: (3y + 4) + (5y +4) = 48$

$\sf{\longrightarrow} \: 8y + 8 = 48$

$\sf{\longrightarrow} \: 8y = 48 - 8$

$\sf{\longrightarrow} \: 8y = 40$

$\sf{\longrightarrow} \: y = \dfrac{40}{8}$

$\sf{\longrightarrow} \: y = 5$

___________________

$\textsf{\underline{Present ages:}}$

$\textsf{A's age-}$

$\sf{\longrightarrow} \: 3(5) = 15$

$\textsf{B's age-}$

$\sf{\longrightarrow} \: 5(5) = 25$

$\textsf{Therefore, A is 15 years old and B is 25 years old.}$