1. The ages of two friends Ani and Biju differ by 3 years. Ani's father Dharam is twice as old
as Ani and Biju is twice as old as his sister Cathy. The ages of Cathy and Dharam differ
by 30 years. Find the ages of Ani and Biju.
Answers
Answer:
The age of Ani is 19 years
The age of Biju is 16 years .
Step-by-step explanation:
Given as :
The present age of Ani = A years
The present age of Biju = B years
Statement I
The ages of two friends Ani and Biju differ by 3 years.
i.e A - B = 3 .......1
statement II
Ani's father Dharam is twice as old as Ani
D = 2 A ........2
statement III
Biju is twice as old as his sister Cathy
i.e B = 2 C .......3
statement IV
The ages of Cathy and Dharam differ by 30 years
D - C = 30 .........4
From 2 and 3 , and 4
2 A - C = 30
Or, 2 A - = 30
i.e 4 A - B = 60 ....5
Solving eq 1 and eq 5
( 4 A - B) - (A - B ) = 60 - 3
Or, ( -B + B ) + ( 4 A - A) = 57
Or, 0 + 3 A = 57
∴ A = 19 years
So, The age of Ani = A = 19 years
Put the value of A in eq 1
19 - B = 3
Or, B = 19 - 3
∴ B = 16 years
So, The age of Biju = B = 16 years
Hence, The age of Ani is 19 years and The age of Biju is 16 years . Answer
Answer:
Let the ages of Ani be A
Let the age of Biju be B
Hence, the age of Dharam = 2 x A = 2A yrs.
The age of Biju sister Ani B/2 yrs
As per the given conditions will solve
Case (i)
When Ani is older than that of Biju
A – B = 3 – – – – – – – – (1) {older by 3 years}
2A−B/2 = 30
4A – B = 60 – – – – – – – – – – – (2)
By subtracting the equations (1) and (2) we get,
3A = 60 – 3 = 57
A = 57/3 = 19
The age of Ani = 19 yrs
The age of Biju is 19 – 3 = 16 yrs.
Case (ii)
When Biju is older than Ani,
B – A = 3 – – – – – – – – – (1) {older by 3 years}
2A − B/2 = 30
4A – B = 60 – – – – – – – – – (2)
Adding the equation (1) and (2) we get,
3A = 63
A = 21
Answer
The age of Ani is 21 yrs
The age of Biju is 21 + 3 = 24 yrs.