Question

1. the area of a square is(100) CM2 . find its perimeter.
2. divide x3-2x+8-x2 by x+2.
3. factories (i)x2-18x40,(ii)a2-10a-75.
4. If 3/4(n+1) and 2/3+1 are equal, find the value of n.
5. find the value of x idc x°,(2×+13°),(3×+10°) and(x-6°) are all the angles of a quadrilateral? ​

Answer 1

Answer:

1. Perimeter of a square=40cm

2. Quotient=x²-3x+4

Remainder=0

3. i.) (x+2)(x-20)

ii.) (a+5)(a-15)

4. n=11/9

5. x=49

Step by step solutions:

1. Let the side of square=x

Area of a square=100cm²

side×side=100cm²

x × x=100cm²

x²=100cm²

x=√100

x=10cm

So,the side of square=x=10

Now,

Perimeter of a square=4×side

=4×10

=40cm

2. See the above picture

3. i.) x²-18x-40

=x²-20x+2x-40

=x(x-20)+2(x-20)

=(x+2)(x-20)

ii.) a²-10a-75

=a²-15a+5a-75

=a(a-15)+5(a-15)

=(a+5)(a-15)

4. 3/4(n+1)=2/3+1

=3/4(n+1)=2+3/3

=3/4(n+1)=5/3

=(n+1)=5/3 × 4/3

=n+1=20/9

= n=20/9-1

= n=20-9/9

=n=11/9

5. Sum of angle of quadrilateral=360°

x+(2x+13)+(3×+10)+(x-6)=360

x+2x+13+3×+10+x-6=360

7x+17=360

7x=360-17

x=343/7

x=49