1 The area of an isoscetes triangular
land whose base side length 10 meter
is 60 square meter find the measure
of remaining sides
Answers
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Step-by-step explanation:
Area of triangle=1/2b×h
60m²=1/2×10m×h
h=60m²/5m
h=12m
The height/altitude of an isosceles∆ divides the it in two equal parts.
Hence, The base of ∆ is 5m.
By using Pythagoras,
H²=(12)²+(5)²
H²=144+25
H=√169
H=13m
Hence, The length of other two sides of the field is 13m.
I hope it is helpful for you!
Thanks for asking!
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