Question

1 The area of an isoscetes triangular
land whose base side length 10 meter
is 60 square meter find the measure
of remaining sides​

Answer 1

Step-by-step explanation:

Area of triangle=1/2b×h

60m²=1/2×10m×h

h=60m²/5m

h=12m

The height/altitude of an isosceles∆ divides the it in two equal parts.

Hence, The base of ∆ is 5m.

By using Pythagoras,

H²=(12)²+(5)²

H²=144+25

H=√169

H=13m

Hence, The length of other two sides of the field is 13m.

I hope it is helpful for you!

Thanks for asking!