1. The circumference of a circle exceeds the
diameter by 16.8cm.find the circumference
of the circle
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Here,
D+16.8= C (1)
C= 2πr (2)
On equating both we have,
2πr= D+16.8 cm
2πD/2=D+16.8 cm(r= D/2)/(change RHS D into 2r)
πD= D+16.8cm
22/7 ×D= D+ 16.8cm
22D= 7(D+16.8cm)
22D= 7D+ 117.6cm
22D-7D= 117.6cm
15D= 117.6cm
D= 117.6cm/15= 39.2cm/5= 7.84cm
r= D/2= 7.84/2cm= 3.92cm
C= 2πr
= 2×22/7 × 3.92
= 44× 0.56cm
= 24.64 cm
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