Question

.
1) The difference of twice the smaller of the two consecutive integers and the larger is 39. Find the
integers and check your answer.​

Answer 1

Answer:

The two integers are -37 and -38

Explanation:

Given

• The numbers are consecutive integers
• The difference between twice the smaller and the larger number is 39

To Find

• The two integers.

Solution

Let the smaller integer = x

The larger integer = x + 1

According to the question

⟹ ( x + 1 ) - 2x = 39

⟹ x + 1 - 2x = 39

⟹ -x + 1 = 39

⟹ -x = 39 - 1

⟹ -x = 38

⟹ x = -38

The smaller integer = x = ( -38)

The larger integer :

⟹ ( x + 1 )

⟹ ( -38 + 1 )

⟹ -37

Double check:

⟹ ( x + 1 ) - 2x = 39

Replace ( x + 1 ) and x by -37 and -38 respectively.

⟹ ( -37 ) - {2( -38 )} = 39

⟹ -37 - ( -76 ) = 39

⟹ -37 + 76 = 39

⟹ 39 = 39

LHS = RHS

hence, checked.

Answer 2

Answer:

let 1st consecutive interger =a

let 2nd consecutive integer =a+1

According to question=

2a-(a+1)=39

2a-a+1=39

a+1=39

a=39-1

a=38

so ,1st consecutive interger=38 and it is also a smaller number

2nd consecutive integer=38+1=39

it is a larger number.