Physics, asked by PhysicsHelper, 1 year ago

1. The dimensions ML⁻¹T⁻² may correspond to
(a) Work done by a force
(b) Linear momentum
(c) Pressure
(d) Energy per unit volume.
Concept of Physics - 1 , HC VERMA , Chapter "Introduction to Physics". Objective questions

Answers

Answered by tiwaavi
19
Hello Dear.

(a) Work done by a force :-
Work done = force × distance
= [ML¹T⁻²] [L]
=ML²T⁻²

(b) Linear momentum :-
p= mv
= [M][LT⁻¹]
=MLT⁻¹

(c)Pressure :-
P= F/A
= [ML¹T⁻²][L²]
=ML⁻¹T⁻² 

(d)Energy per unit volume :-
E = (force × displacement)/volume
=[ML¹T⁻²][L] / [L³]
= ML⁻¹T⁻²

Hence (c) & (d) is the correct option whose dimension is ML⁻¹T⁻² .


Hope it Helps.
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