Question

1 » The distance of the point (3,5 ) from the line 2x + 3y-14 =0 measured parallel to the line x -2y =1 is

a) 7/√15

b ) 7/√13

c ) √5

d) √13 .




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Answer 1

Hey Mate
your answer is here

first find a line which is parallel to x-2y= 1 and passing through (3,5)


so,slope = 1/2

y-5 = (1/2)x-3

x-2y+7 = 0

now find the intersection of line x-2y+7 = 0 & 2x+3y-14 = 0

so, required point is (1,4)

so,

distance = root of (3-1)^2+(4-5)^2 = 4+1 = root5

Answer 2

Hay mate here is your answer ✌❤☺


Tirst find a line which is parallel to x-2y 1 and passing through (3,5)

so,slope 1/2

y-5 -(1/2)x-3

now find the intersection of line x-2y+7=0& 2x+3y-14=0



so, required point is (1,4)

SO distance-


= root of (3-1)²+(4-5) ² = 4+1 = √5


Hope it will help you ☺❤