Question

(1) the energy associated with the first orbit in the hydrogen atom is -2.18 × 10^-18 J/atom. whT us the energy associated qith yhe fifth orbit ?

(2) Calculate the radius of Bohr's fifth orbit for hydrogen atom.​

Answer 1

Answer:

Mass (m) = 5 Kg

Momentum (p) = 10 Kg m/s

Force applied (F)= 0.2N for t= 10 seconds

Solution:

Momentum (p)=m∗u=10Kgm/s

(Here u is the velocity at which the object is moving)

p=5∗u=10

u=105=2m/s

F=m∗a=0.2N

( When force is applied to the moving object then object will accelerate at 'a')

F=5∗a=0.2

a=0.25=0.04m∗s−2

Now, using Newton's laws of motion we will find the new velocity (v) of the object

v=u+a∗t

v=2+0.04∗10=2.4m∗s−1

Change in kinetic energy is

ΔK.E=12m∗v2−12m∗u2

ΔK.E=12∗m(v2−u2)

ΔK.E=12∗5∗(2.42−22)

ΔK.E=0.5∗5∗(5.76−4)=4.4J

Increase in kinetic energy will be 4.4 joules.