Question

1. The energy of separation of an electron is 30.6 e V moving in an orbit of Li2+ . Find out the
number of waves made by the electron in one complete revolution in the orbit.​

Answer 1

Answer:

Explanation:

According to Bohr’s postulate of angular momentum, in the 3rd orbit

Mur = n h/2π

Mur = 3 (h/2π) …..(i) [n = 3]

According to de Broglie relationship

λ = h/mu ….(ii)

Substituting (ii) in (i), i get!

(h/λ) r = 3 (h/2π)

3λ = 2πr

Easy method!!

Number of waves = n(n - 1)/2

3(3 - 1)/2 = 3 * 2/2 = 3

hope it helps!!