Question

1. The equation of a transverse wave in a stretched string is = 5 sin 2 [ t/0.04 - x/50] m. Find the wave velocity

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Answer 1

Explanation:

Equations of wave y=5sin(

0.04

t

−

4

x

)

The standard equation of a wave in the given from is

y=asin(ωt−

λ

2πx

)

Comparing the given equation with the standard equation, we get

a=5

and ω=

0.04

1

=25and λ=8π

Therefore, maximum velocity of particles of the medium.

v

max

=aω=5×25

=125csm

−1

=1.25ms

−1