Question

1. The equation of projectile is y = √3x - 1/2gx². The<br />velocity of projection is:​

Answer 1

Answer:

Equation of motion of projectile id :

y = x*tan(theta) - 0.5*g*x^2/( ucos(theta))^2

So comparing it with original equation , tan (theta) = root(3)

Theta = 60°

(u*cos(theta))^2 =1

So, u^2 * (cos(60))^2 =1

u= 2m/s

Explanation: