Question

1.
The equation of the circle with centre (3,-2) and radius 3 is
a) x² + y2 - 6x + 4y + 4 = 0
b) x² + y2 - 4x+6y +9 = 0
c) x² + y2 +14x+6y - 42 = 0
d) x² + y2 +2x+16y+40 = 0)​

Answer 1

C is the correct answer mate.......