Math, asked by shalinisubhashshirsa, 1 month ago

1. The fencing of a square garden is 32m in length.
How long is one side of the garden?​

Answers

Answered by GODLYxCHAOS
0

Answer:

One side of the garden is 8m.

Step-by-step explanation:

Perimeter of a square = 4a (a = side)

∴ side = (32/4)m = 8m

Answered by jackzzjck
9

Answer:

The Length of one side around the garden = 8m.

✳Solution✳

The length of Fencing around the square garden = 32m.

We know that all the sides of a square are equal in dimension .

The equation of  perimeter of square = 4 × Side = 4×a

Fencing is done along the side , That is along the perimeter of the square .

So , 32m is the perimeter of the given Square.

\implies

32 = 4×a

\implies

\sf \dfrac{32}{4} = 8m.

∴ Side (a) of the square garden = 8m.

✳The Square Garden Is✳

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(4,0){2}{\line(0,1){4}}\multiput(0,0)(0,4){2}{\line(1,0){4}}\put(-0.5,-0.5){\bf D}\put(-0.5,4.2){\bf A}\put(4.2,-0.5){\bf C}\put(4.2,4.2){\bf B}\put(1.5,-0.6){\bf\large \ 8m}\put(4.4,2){\bf\large \ 8m}\end{picture}

✳FORMULA OF PERIMETER OF 3 MORE COMMAN SHAPES✳

Rectangle

Perimeter = 2(l+b)

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large l}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large b }\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

Triangle

Perimeter = side + side + side

\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.85,3.2){$\bf A$}{\2}\put(0.5,-0.3){$\bf C$}\put(5.2,-0.3){$\bf B$}\end{picture}

Circle

Perimeter = 2πr

\bigstar Perimeter of a circle is also called it's circumference

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\put(0,0){\line(1,0){2.3}}\put(0.5,0.3){\bf\large r}\end{picture}

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