If in a trapezium ABCD, AB is parallel to CD,∠A = ∠D = 90°,∠C = 120°, DC= 28 cm and BC = 40 cm, then find the lengths of AB and AD. Also find the perimeter of ABCD.
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Trapezium ABCD is drawn in figure.
AE=(18−12) cm =6 cm
Δ AED is a right-angled Δ
∴(AD)
2
+(ED)
2
+(AE)
2
10
2
=h
2
+6
2
∴h=
100−36
h=8 cm
Area of trapezium=
2
1
×Sum of parallel sides×Distance between them.
=
2
1
(18+12)×8
=
2
1
(30)×8
=30×4 =120 cm
2
.
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