Question

1)The floor of a building consists of 500 tiles which are square shaped. Each side of tile
measures 42cın. Find the cost of polishing the floor, if cost percm2is 5.40​

Answer 1

Total no. of tiles =2550
Since the tiles are in the shape of rhombus and diagonals are of length 20cm and 28cm.
Therefore,
d
1
​
=20cm
d
2
​
=28cm
Area of one tile = Area of rhombus
As we know that area of rhombus is given as-
A=
2
1
​
×d
1
​
×d
2
​

Therefore,
Area of 1 tile =
2
1
​
×20×28=280cm
2

∴ Area of 2550 tiles =2550×280=714000cm
2
=71.4m
2

Given that the cost of polishing is Rs.25 per m
2
.
Therefore,
Cost of polishing the floor =25×71.4=Rs.1785
Hence the cost of polishing the floor is Rs.1785.

Answer 2

Answer:

The cost is 47,62,800 rupees.

Step-by-step explanation:

The number of tiles = 500

Sides of a square (a) = 42cm

Area of square = a²

Area of the square = (42)²

= 1764 cm²

Cost of polishing one cm² = Rs. 5.40

Cost of polishing 1764 cm² = 1764 x 5.40

= Rs. 9525.6

Cost of polishing one tile = Rs. 9525.6

Cost of polishing 500 tiles = 500 x 9525.6

= Rs.47,62,800

Thus the cost of polishing all the tiles is 47,62,800 rupees .