Question

(1) The following determinants are obtained from the simultaneous equations in varible
x and y.
The solutions for this equations are x=3 and y = – 2, then find the value of
‘a' and 'b'. Also form the original simultaneous equations having this solution.​

Answer 1

Answer:

Solve the systems of equations using the substitution method

{y=2x+4y=3x+2

We substitute the y in the top equation with the expression for the second equation:

2x+44−22===3x+23x−2xx

To determine the y-value, we may proceed by inserting our x-value in any of the equations. We select the first equation:

y=2x+4

We plug in x=2 and get

y=2⋅2+4=8

We have thus arrived at precisely the same answer as in the graphic solution.

The elimination method requires us to add or subtract the equations in order to eliminate either x or y, often one may not proceed with the addition directly without first multiplying either the first or second equation by some value.